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VBA/Excel/Access/Word/Data Type/Integer - История изменений
2026-04-07T08:58:32Z
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http://www.vbex.ru/index.php?title=VBA/Excel/Access/Word/Data_Type/Integer&diff=1843&oldid=prev
в 16:33, 26 мая 2010
2010-05-26T16:33:00Z
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http://www.vbex.ru/index.php?title=VBA/Excel/Access/Word/Data_Type/Integer&diff=1844&oldid=prev
Admin: 1 версия
2010-05-26T12:48:20Z
<p>1 версия</p>
<p><b>Новая страница</b></p><div>==Add integer together==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub Accumulate()<br />
Dim n As Integer<br />
Dim t As Integer<br />
For n = 1 To 10<br />
t = t + n<br />
Next n<br />
MsgBox " The total is " & t<br />
End Sub<br />
</source><br />
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==Add two numbers together==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub addNumbers()<br />
"Declare the variables<br />
Dim intNumber1 As Integer<br />
Dim intNumber2 As Integer<br />
Dim intSum As Integer<br />
"Create InputBoxes to enter numbers<br />
intNumber1 = InputBox("Enter the first number")<br />
intNumber2 = InputBox("Enter the second number")<br />
"Add numbers<br />
intSum = intNumber1 + intNumber2<br />
" Create an output<br />
Debug.Print "The numbers entered were " & intNumber1 & " and " & intNumber2<br />
End Sub<br />
</source><br />
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==Input and Output==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub addNumbers()<br />
Dim intNumber1 As Integer<br />
Dim intNumber2 As Integer<br />
Dim intSum As Integer<br />
"Create InputBoxes to enter numbers<br />
intNumber1 = InputBox("Enter the first number")<br />
intNumber2 = InputBox("Enter the second number")<br />
End Sub<br />
</source><br />
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==Integer number==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub MyNumber()<br />
Dim intNum As Integer<br />
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intNum = 23.11<br />
MsgBox intNum<br />
End Sub<br />
</source><br />
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==Local Integer variable==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Public Sub TestLocal1()<br />
Dim intVariable1 As Integer<br />
intVariable1 = intVariable1 + 1<br />
Debug.Print intVariable1<br />
End Sub<br />
</source><br />
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==Overflow error==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub macro_overflow()<br />
Dim l As Integer<br />
l = 255 * 256 "overflow error<br />
End Sub<br />
Sub macro_no_overflow()<br />
Dim l As Long<br />
l = 255& * 256 "now it works<br />
End Sub<br />
</source><br />
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==Select Case statement with Integer value==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub cmdCase_Click()<br />
Dim intAge As Integer<br />
intAge = 12<br />
Select Case intAge<br />
Case 0<br />
MsgBox "You Must Enter a Number"<br />
Case 1 To 18<br />
MsgBox "You Are Just a Kid"<br />
Case 19, 20, 21<br />
MsgBox "You are Almost an Adult"<br />
Case 22 To 40<br />
MsgBox "Good Deal"<br />
Case Is > 40<br />
MsgBox "Getting Up There!"<br />
Case Else<br />
MsgBox "You Entered an Invalid Number"<br />
End Select<br />
End Sub<br />
</source><br />
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==The Integer data type is the most efficient way of handling numbers from -o /td><br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub intDemo()<br />
Dim intMyVar As Integer<br />
For intMyVar = 1 To 300<br />
"repeat actions<br />
Next intMyVar<br />
End Sub<br />
</source><br />
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==Use If statement with Integer==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub ifTest()<br />
Dim intNum As Integer<br />
Dim strMessage As String<br />
intNum = 12<br />
If intNum > 10 Then<br />
strMessage = "The number is " & intNum<br />
End If<br />
Debug.Print strMessage<br />
End Sub<br />
</source></div>
Admin