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VBA/Excel/Access/Word/Date Functions/DateAdd - История изменений
2026-04-05T07:38:56Z
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в 16:33, 26 мая 2010
2010-05-26T16:33:00Z
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Admin: 1 версия
2010-05-26T12:48:47Z
<p>1 версия</p>
<p><b>Новая страница</b></p><div>==Add value to Date==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub AddADay()<br />
Dim dtInitialDate As Date<br />
dtInitialDate = DateAdd("d", 1, dtInitialDate)<br />
Debug.Print dtInitialDate<br />
End Sub<br />
</source><br />
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==DateAdd(interval, number, date) returns a Variant/Date containing the date of the specified interval after the specified date==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub dateDemo2()<br />
Debug.Print DateAdd("m", 1, "6/3/06"); returns; 7 / 3 / 2006#<br />
End Sub<br />
</source><br />
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==DateAdd returns the result of adding or subtracting a specified period of time to a date:==<br />
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<!-- start source code --><br />
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<source lang="vb"><br />
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Sub DateAddExample()<br />
Debug.Print DateAdd("d", 3, Now)<br />
"Today plus 3 days<br />
Debug.Print DateAdd("m", 3, Now)<br />
"Today plus 3 months<br />
Debug.Print DateAdd("yyyy", 3, Now)<br />
"Today plus 3 years<br />
Debug.Print DateAdd("q", 3, Now)<br />
"Today plus 3 quarters<br />
Debug.Print DateAdd("ww", 3, Now)<br />
"Today plus 3 weeks<br />
Debug.Print DateAdd("ww", -3, Now)<br />
"Today minus 3 weeks<br />
End Sub<br />
</source></div>
Admin